Question #a4f96

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Question #a4f96

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Answer 1 · 2017-08-19T00:25:17

$F = 21.9$ $F = 21.9$ $N$ $"N"$

Explanation:

We're not given any information regarding the slope of the incline to determine the gravitational force opposing the motion, nor the friction between the sled and the incline. I will neglect these and assume a simplified work example.

The equation for one-dimensional work is

$ul(W = Fs$

where

$W$ is the work
$F$ is the magnitude of the force
$s$ is the distance it traveled while the force was acting

We know:

$W = 379.5$ $"J"$
$s = 17.3$ " $m"$

So we have

$color(red)(F) = W/s = (379.5color(white)(l)"J")/(17.3color(white)(l)"m") = color(red)(ulbar(|stackrel(" ")(" "21.9color(white)(l)"N"" ")|)$

The magnitude of the force she exerted is thus $color(red)(21.9color(white)(l)"newtons"$ .

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Question #a4f96

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