Question #2d18a

1 Answer
P dilip_k
Jan 16, 2017

The balanced equation of reaction of #CaCO_3# with #HCl# is as follows

#CaCO_3+2HCl->CO_2+H_2O+CaCl_2#

Molar mass of #CaCO_3=(40+12+3*16)g"/mol"=100g"/mol"#

So 1g #CaCO_3=1/100mol=0.01mol#
Let 2000cc or #2L" "HCl# solution contains #xmol" "HCl#

As per equation the reacting ratio of #CaCO_3# and #HCl# is #1:2#
Hence #0.01/x=1/2#

So #x=0.02mol# (Assuming the acid has been completely nutralized by 1g #CaCO_3#)

Hence the strength of the #HCl# solution is #c=(0.02mol)/(2L)=0.01M#

So pH if the solution is

#=-logc=-log(0.01)=2#

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