If #19*mol# of #H_2(g)# react with stoichiometric #N_2(g)#, what molar quantity of ammonia results?

1 Answer
anor277
Jul 6, 2017

A bit under #13*mol# of ammonia..........

Explanation:

You have the stoichiometric equation........

#N_2(g) + 3H_2(g) stackrel("catalysis")rarr2NH_3(g)#

And clearly, if #19*mol# dihydrogen react completely (which is NOT an altogether probable outcome) then by the stoichiometry we get #19/3xx2*mol=12.7*mol# with respect to ammonia, #NH_3#.......

What is the significance of this ammonia synthesis? Do you think that this reaction is widely performed?

Related questions
See all questions in Mole Ratios
Impact of this question
1540 views around the world
You can reuse this answer
Creative Commons License