Question #d332d

1 Answer
Mar 16, 2017

You would need more than 6 days for plan B to cost less

Explanation:

Let the count of days be #d#

Plan A#->$230xxd->$230d#

Plan B#->$1000+$35xxd->$1000+$35d#
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

For Plan B to cost less we have:

#$230d>$1000+$35d#

Subtract #$35d# from both sides

#$230d-$35d>$1000#

#$195d>$1000#

Divide both sides by $195

Did you know you can treat units of measurement the same way you do the numbers. So you can cancel them out. $ is a unit of measurement!

#d> (cancel($)1000)/(cancel($)195) =5.128...#days

The wording of the question implies that the smallest unit of count of time is 1 day. As you may not have part of a day in this context you must round up. So 5.128.. days is read as 6 days

You would need more than 6 days for plan B to cost less