Question #c8da8

1 Answer
Douglas K.
Jan 13, 2017

The balanced equation is:

#Ca(OH)_2 + CO_2 to CaCO_3 + H_2O#

Explanation:

From the equation, please observe that 1 mole of #Ca(OH)_2# produces:

#(0.962" mole "Ca(OH)_2)/1(1" mole "CaCO_3)/(1" mole "Ca(OH)_2)#

The molar mass of #CaCO_3# is 100 g:

#(0.962cancel(" mole "Ca(OH)_2))/1(1cancel(" mole "CaCO_3))/(1cancel(" mole "Ca(OH)_2))(100" g "CaCO_3)/(1cancel(" mole "CaCO_3)) = 96.2" g "CaCO_3#

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