Question #eae28

1 Answer
A08
Aug 27, 2017

I get this.

Explanation:

The problem consists of sum of two pressures which the pump must create

  1. Pressure due to height of 40 m of water column
  2. Pressure due to jet of water at a rate of 5ms^-1

For 1. Assuming unit area, Force=Pressure

Pressure due 40m water column P_1=mg=rhoxx"volume"xxg
P_1=1000xx(40xx1)xx9.81=392400pa

For 2. Assumed area of the jet be unit area.
Speed of water outlet from jet =5 ms^-1.
Total mass of water thrown out per sec= rhoxx1xx5=5000kg

Pump must exert pressure to support weight of this additional column of water of unit area=5000xxg=49050N

For unit area of jet pressure P_2=49050pa

Total pressure of the pumpP=P_1+P_2=392400+49050=441450pa

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