Question #7abf9

1 Answer
Dec 28, 2017

"Critical angle"=pi/6=30^circ

Explanation:

The equation for critical angle is:
sinC=n_1/n_2, where:

  • C = critical angle
  • n_1 = boundary medium
  • n_2 = initial medium

In this case n_1 is the vacuum as it is the medium acting as a boundary, while n_2 is the other medium, as the light is travelling through that medium.

n_1=1

sinC=1/2

C=sin^(-1)(1/2)=pi/6=30^circ