Question #e0a62

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Answer 1 · 2017-08-06T01:39:23

I got $25m$

We could use the relationship from Kinematics:

$v_f^2=v_i^2+2ad$

that, with your data for the first part, gives:

$15^2=30^2+2a*75$

solving for $a$ :

$a=-4.5m/s^2$

we use this acceleration in $v_f^2=v_i^2+2ad$ again for the second part where the final velocity will be zero and initial $15m/s$ :

$0^2=15^2-2*4.5*d$

$d=25m$