Question #e355e

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Question #e355e

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Answer 1 · 2017-01-04T08:08:58

$y=40^@$

Explanation:

Given that $AB=AC and angleC=40^@, => DeltaABC$ is an isosceles triangle.

An isosceles triangle is a triangle that has two sides of equal length.
The unequal side of an isosceles triangle is usually referred to as the 'base' of the triangle. In the figure, $BC$ is the base.
The base angles of an isosceles triangle are always equal. In the figure, the angles $angleB$ and $angleC$ are the same.

Given that $angleC=40^@$
$=> angleB=angleC=40^@$
$=> angleA=180-(angleB+angleC)=180-(40+40)=100^@$
Given $angleA=2y+20$
$=> 2y+20=100^@$
$=> 2y=80^@$
$=> y=40^@$

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Question #e355e

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