What is the range of f(x)=–5-2(x+3)^2?

1 Answer
Dec 31, 2016

The range is {y|y<="-5"}.

Explanation:

The range of a function is simply all the possible outputs that function can give.

Mathematically speaking, a number y is in the range of a function f when we can find an x such that f(x)=y.

There are a couple of ways to find the range of a function. For f(x)="-5"-2(x+3)^2, the easiest way is to see that f is a certain type of function—a parabolic function. As such, there is no limitation on the x-values we can input (i.e. the domain is RR), but there is an easy-to-see limitation on the output (or y) values f(x) can give.

Take a look at that squared bit—the (x+3)^2. We know this can't be less than 0, because the square of a number is always positive (or 0, if we're squaring 0).

So (x+3)^2 is no less than 0. Meaning, 2(x+3)^2 is also no less than 0. Then -2(x+3)^2 is no more than 0, and thus "-"5-2(x+3)^2 is no more than -5.

In math:

color(white)(f(x)="-5"-2)(x+3)^2>=0
color(white)(f(x)="-5"-)2(x+3)^2>=0
color(white)(f(x)="-5")-2(x+3)^2<=0" "(note the change to <=)
f(x)="-5"-2(x+3)^2<="-5"

The end result: f(x)<="-5".
And so our range is "all numbers y such that y is at most -5", or in math:

{y|y<="-5"}.

Bonus:

The shortcut to finding the range of a parabolic equation f(x)=a(x-h)^2+k is to use this:

Range of f(x) is {({y|y>=k}" when "a>0),({y|y<=k}" when "a<0):}

Just choose the correct option depending on the value of a. (In this example, a was less than 0, so we would choose {y|y<=k}, and plug in our k-value of -5.)