Question #b38a1

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Question #b38a1

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Answer 1 · 2016-12-28T05:49:29

$144 N$ $144N$

Explanation:

Let magnitude of the force be $F$ $F$ ,
Using Newton's second law of motion we obtain constant acceleration $a$ $a$ as

$F = m a$ $F=ma$

Inserting given value
$F = 16 a$ $F=16a$
$\Rightarrow a = \frac{F}{16} m s^{- 2}$ $=>a=F/16ms^-2$ ......(1)

Assuming that initially the body is at rest, final velocity $v$ $v$ of body after $3 s$ $3s$ can be calculated with the help of kinematic expression

$v = u + a t$ $v=u+at$

Inserting given values and using equation (1) we get
$v = 0 + \frac{F}{16} \times 3$ $v=0+F/16xx3$
$\Rightarrow v = \frac{3 F}{16} m s^{- 1}$ $=>v=(3F)/16ms^-1$ .....(2)

Once the force is removed the body moves at a constant velocity for next $3 s$ $3s$ . Distance $s$ $s$ covered in time is

$s = v t$ $s=vt$

Inserting given values and using equation (2) we get
$81 = \frac{3 F}{16} \times 3$ $81=(3F)/16xx3$
$\Rightarrow \frac{F}{16} = 9$ $=>F/16=9$

Solving for force we get
$F = 9 \times 16 = 144 N$ $F=9xx16=144N$

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Question #b38a1

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