Question #e40ab

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Answer 1 · 2017-08-08T10:17:53

$2400 \frac{A}{sec}$ $2400 A/sec$

As everyone knows that induced emf in parallel inductors is same even they holds different inductance values.

We know that,

$E = - N \frac{ϕ}{t}$ $E= -N (phi)/t$

$E = - N (\frac{ϕ}{t}) (\frac{i}{i})$ $E= -N ((phi)/t)(i/i)$

$E = - (N (\frac{ϕ}{i})) (\frac{i}{t})$ $E=-(N(phi/i))(i/t)$

$E = L \frac{i}{t}$ $E=Li/t$

[ $'.'$ $L=(phiN)/t$ ]

Let rate of change of current be R.

$:.E=LR$ $---->(1)$

From equation (1)

Voltage across inductor having inductance L & 2L respectively,

$V_L=LR_1$ $---->(2)$

$V_(2L)=2LR_2$ $----->(3)$

since voltage induced in parallel inductors is same, hence

$LR_1=2LR_2$

$R_1=2R_2$

since ,
$R_2= 1200 A/sec$

hence

$R_1= 2400 A/sec$