A gas occupies a volume of #12.7mL# at #295K# in a piston; what volume will it occupy at #284*K#?

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Answer 1 · 2017-08-07T07:39:38

We use old Charles' law.....#V_1/T_1=V_2/T_2#, which establishes the influence of absolute temperature on gaseous volume......

We solve for #V_2=V_1/T_1xxT_2#

#(12.7*mL)/(295*K)xx284*K=12.2*mL#

AS expected, the volume is slightly reduced at slightly reduced temperature.

A gas occupies a volume of #12.7*mL# at #295*K# in a piston; what volume will it occupy at #284*K#?