An object moves in a straight line at $30 \frac{k m}{h r}$ $30 (km)/(hr)$ for 5 minutes. What will be the distance it has travelled at the end of this motion?

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An object moves in a straight line at $30 \frac{k m}{h r}$ $30 (km)/(hr)$ for 5 minutes. What will be the distance it has travelled at the end of this motion?

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Answer 1 · 2017-01-22T01:44:03

Since 5 minutes is $\frac{1}{12}$ $1/12$ of an hour, the distance is $d = (30 \frac{k m}{h r}) \times (\frac{1}{12} h r) = 2.5 k m$ $d=(30(km)/(hr))xx(1/12hr) = 2.5 km$

Explanation:

By definition

$v e l o c i t y = \frac{d i s p l a c e m e n t}{t i m e}$ $velocity=(displacement)/(time)$

So, displacement (which is the same as distance in this situation of straight line motion) is

$d i s p l a c e m e n t = v e l o c i t y \times t i m e$ $displacement=velocityxxtime$

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An object moves in a straight line at $30 \frac{k m}{h r}$ $30 (km)/(hr)$ for 5 minutes. What will be the distance it has travelled at the end of this motion?

1 Answer

Explanation:

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An object moves in a straight line at 30kmhr30 (km)/(hr) for 5 minutes. What will be the distance it has travelled at the end of this motion?

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An object moves in a straight line at $30 \frac{k m}{h r}$ $30 (km)/(hr)$ for 5 minutes. What will be the distance it has travelled at the end of this motion?