Question #c4621

1 Answer
Douglas K.
Dec 10, 2016

There are 2 real solutions: x ≈ ± 2.63571322227139...

Explanation:

The equations cannot be solved by algebraic methods. You can solve the equations:

-2sin(x) - ln(-x) = 0; -oo < x < 0−2sin(x)−ln(−x)=0;−∞<x<0

2sin(x) - ln(x) = 0; 0 < x < oo2sin(x)−ln(x)=0;0<x<∞

Using a numerical analysis method, for example Newton's Method and a computation tool like Excel or MatLab.

I used WolframAlpha to obtain the two values:

x ≈ ± 2.63571322227139...

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