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Answer 1 · 2016-12-09T14:27:47

Molar mass of propane

#C_3H_8=(3*12+8*1)"g/mol"=44"g/mol"#

So 50g of #C_3H_8# = #(50g)/(44g/"mol")=25/22 mol#

Molar mass of #O_2=2*16=32"g/mol"#

The given balanced equation shows that

1 mole propane requires 5 moles #O_2#

So #25/22 mol# propane requires

#25/22xx5molO_2=25/22xx5xx32gO_2=181.8gO_2#