Question #6fd64

1 Answer
Douglas K.
Dec 7, 2016

Use the factor-label method (a.k.a. Dimensional Analysis):

#(2226" kJ")/(1 " mole") (1" mole")/(342" g")(1000" g")/(1" kg")#

Cancel the units:

#(2226" kJ")/(1cancel(" mole")) (1cancel(" mole"))/(342cancel(" g"))(1000cancel(" g"))/(1" kg")#

Perform the multiplication and division:

#(2226" kJ")/(1cancel(" mole")) (1cancel(" mole"))/(342cancel(" g"))(1000cancel(" g"))/(1" kg") = 6509"kj"/"kg"#

Related questions
See all questions in Enthalpy
Impact of this question
3112 views around the world
You can reuse this answer
Creative Commons License