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Question #0857c

1 Answer

Dec 10, 2016

#1#

Explanation:

To evaluate #2x-5# at #x=3#, we replace every instance of #x# in the given expression with a #3#.

#2color(red)(x)-5 -> 2color(red)((3))-5#

Then we evaluate the new expression.

#2(3)-5 = 6-5 = 1#

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