Length of a rectangle exceeds its width by $12$ $12$ inches and its area is $768$ $768$ square inches. Write the equation which solves this problem?

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Answer 1 · 2016-12-07T08:24:46

The desired quadratic equation is $w^{2} + 12 w - 768 = 0$ $w^2+12w-768=0$

Let the width of the rectangular window be $w$ $w$ inches.

As length exceeds width by $12$ $12$ inches, it s $w + 12$ $w+12$ inches.

Hence area is $w (w + 12)$ $w(w+12)$ and as it is $768$ $768$ square inches, we have

$w (w + 12) = 768$ $w(w+12)=768$

or $w^{2} + 12 w = 768$ $w^2+12w=768$

or $w^{2} + 12 w - 768 = 0$ $w^2+12w-768=0$

Length of a rectangle exceeds its width by 121212 inches and its area is 768768768 square inches. Write the equation which solves this problem?