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Question #bbc8e

1 Answer

Dec 10, 2016

We'll turn this into a ratio problem, after we convert 160 mL to 0.160L

Explanation:

First question:

#(0.160L)/(1m^2)=(X)/(24.25m^2)->#

#X=0.160L//cancelm^2xx24.25cancelm^2=3.88L#

Second question:
#(0.160L)/(1m^2)=(1.92L)/Y->#

#Y=(1.92cancelL)/(0.160cancelL//m^2)=12m^2#

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