Question #eaa82

2 Answers
Dec 2, 2016

Approx. 4g

Explanation:

The percentage mass of magnesium in magnesium carbonate, MgCO3:

=Molar mass of metalMolar mass of magnesium carbonate=24.305gmol184.32gmol1×100%=28.8%

And thus in a 13.9g sample, there are 28.8%×13.9g4g

Dec 2, 2016

The Answer is approximately
4g

Explanation:

There is another way to consider this question Atomic wt of all atoms in the compound are as follows:
C=12,Mg=24,O=16
Wt of compound = CMgO3=12+24+16(3)=84
It means 84 gm CMgO3 gives 24 gm Magnesium
Therefore 13.9 g CMgO3 gives 248413.9=3.974gm