Question #7ce2b

1 Answer
Dec 1, 2016

This expression simplifies to csctheta.

Explanation:

We put on a common denominator.

=>(costheta(1 + costheta))/(sintheta(1 + costheta)) + (sintheta(sin theta))/(sintheta(1 + costheta))

=>(costheta + cos^2theta + sin^2theta)/(sin theta(1 + costheta))

We know that cos^2x + sin^2x = 1.

=>(1 + costheta)/(sintheta(1 + costheta)

=>1/sintheta

By the reciprocal identities, 1/sinx = cscx.

=>csctheta

Hopefully this helps!