Question #7ce2b
1 Answer
Dec 1, 2016
This expression simplifies to
Explanation:
We put on a common denominator.
=>(costheta(1 + costheta))/(sintheta(1 + costheta)) + (sintheta(sin theta))/(sintheta(1 + costheta))
=>(costheta + cos^2theta + sin^2theta)/(sin theta(1 + costheta))
We know that
=>(1 + costheta)/(sintheta(1 + costheta)
=>1/sintheta
By the reciprocal identities,
=>csctheta
Hopefully this helps!