Question #000d5

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Answer 1 · 2016-12-15T05:16:22

Given $cosA=5/13 and sinA=12/13$

Now when $theta=pi+A$

$sintheta=sin(pi+A)=-sinA=-12/13$

$costheta=cos(pi+A)=-cosA=-5/13$

when $theta=2pi-A$

$sintheta=sin(2pi-A)=-sinA=-12/13$

$costheta=cos(2pi-A)=cosA=5/13$

when $theta=3pi-A$

$sintheta=sin(3pi-A)=sinA=12/13$

$costheta=cos(3pi-A)=-cosA=-5/13$

when $theta=pi/2+A$

$sintheta=sin(pi/2+A)=cosA=5/13$

$costheta=cos(pi/2+A)=-sinA=-12/13$