Question #fd3f5
1 Answer
Dec 1, 2016
Explanation:
I have interpreted this question as follows. Please contact me if my interpretation is incorrect.
#7/3=-10+3/(4-c)# add 10 to both sides.
#7/3+10=cancel(-10)cancel(+10)+3/(4-c)#
#rArr7/3+30/3=3/(4-c)#
#rArrcolor(red)(37)/color(blue)(3)=color(blue)(3)/color(red)(4-c)#
#color(blue)"cross-multiplying"#
#rArrcolor(red)(37(4-c))=color(blue)(3)xxcolor(blue)(3)# divide both sides by 37
#rArr4-c=9/37# subtract 4 from both sides.
#cancel(4)cancel(-4)-c=9/37-4=9/37-148/37=-139/37#
#rArr-c=-139/37rArrc=139/37#
