Question #8c8b6

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Answer 1 · 2016-11-27T01:09:41

given
Let acceleration of the system be #ams^-2# and Tension be T N

also let #g->"acceleration due to gravity"=9.8ms^-2#

Considering the net force acting upward on the combination of 6kg and 4kg combined block system we can write

#T-10gsin30^@=10a.......(1)#

Again considering the net force acting downward on the 9kg block we can write

#9g-T=10a.......................(2)#

Adding (1) and (2) we get

#9g-10gsin30^@=20a#

So #a=(9g-10gsin30^@)/20=(9g-10gxx1/2)/20#

#=>a=g/5=9.8/5ms^-2=1.96ms^-2#