Question #2ec24

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Answer 1 · 2016-11-23T15:05:26

Given
$sinA=12/13 and A" is not in 1st quadrant"$

So $A$ must be in 2nd quadrant

Hence $A=sin^-1(12/13)=112.62^@$

Again

$cosB=3/5 and B" is not in 1st quadrant"$

So $B$ must be in 4th quadrant

Hence $A=cos^-1(3/5)=306.87^@$

So $A+B=112.62+306.87=419.49^@$

Now $(419.49-360)^@=59.49^@$

Hence $A+B->$ In the first quadrant.