Question #bb059

1 Answer
Dec 18, 2016

sin((29pi)/12)

=sin(2pi+(5pi)/12)

=sin((5pi)/12)

=sqrt(1/2(1-cos((2*5pi)/12)

=sqrt(1/2(1-cos((5pi)/6))

=sqrt(1/2(1-cos(pi-pi/6))

=sqrt(1/2(1+cos(pi/6))

=sqrt(1/2(1+sqrt3/2)

=sqrt(1/8(4+2sqrt3)

=sqrt(1/8(sqrt3+1)^2

=(sqrt3+1)/(2sqrt2)