Question #132b8

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Answer 1 · 2016-11-18T00:54:20

Given

$2C(s)+O_2(g)->2CO(g),DeltaH=-221" kJ/mol"$

$=>C(s)+1/2O_2(g)->CO(g),DeltaH=-110.5" kJ/mol"....(1)$

$2CO(g)+O_2(g)->2CO_2(g),DeltaH=-556" kJ/mol"$

$=>CO(g)+1/2O_2(g)->CO_2(g),DeltaH=-228" kJ/mol".... (2)$

Adding (1) and (2) we get

$C(s)+O_2(g)->CO_2(g),DeltaH=-338.5" kJ/mol"$