Question #c8eb0

1 Answer
anor277
Nov 18, 2016

You have been given a series of stoichiometric equations.....

Explanation:

For a. 2Al+3Cl_2 rarr 2AlCl_3

Two equivalents, 2 moles if you like, of aluminum metal react with 3 equiv of dichlorine gas to give 2 equiv aluminum trichloride.

You starting conditions propose that you have 3.6 mol of aluminum metal, and 5.3 mol of Cl_2 gas. Clearly (?), there is insufficient chlorine gas for all the metal to react (given the stoichiometry, 3.6 mol of metal require 5.4 mol of bimolecular chlorine gas, and you only have 5.3 mol of Cl_2 gas.

And thus here, Cl_2 gas is the limiting reagent, which governs the extent of the reaction. At most 5.3xx2/3*mol aluminum chloride can be generated given the limiting quantity of chlorine.

I am reluctant to do the remaining problems, because I think you should work thru them yourself. You have been given balanced chemical equations that describe the equivalence, the stoichiometry. Make an attempt, and someone here will help you.

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