Question #a1253
1 Answer
Here's what I got.
Explanation:
The concentration of hydronium cations,
#color(blue)(ul(color(black)("pH" = - log(["H"^(+)])))#
To find the concentration of hydrogen ions, rearrange the above equation as
#log(["H"^(+)]) = - "pH"#
This can be written by using powers of
#10^(log(["H"^(+)])) = 10^(-"pH")#
which is equivalent to
#["H"^(+)] = 10^(-"pH")#
Plug in your value to find
#color(darkgreen)(ul(color(black)(["H"^(+)] = 10^(-2.89) = 1.3 * 10^(-3)"M")))#
The answer is rounded to two sig figs, the number of decimal places you have for the pH of the solution, because it does not depend on the volume of the sample.
The number of moles of hydrogen ions, however, does depend on the volume of the sample, so it will be rounded to one sig fig.
Now, molarity is defined as the number of moles of solute present in one liter of solution. In your case, a
As you know, one liter is equivalent to
#"1 L" = "1 dm"^3 = 10^3"cm"^3#
This means that your sample contains
#30 color(red)(cancel(color(black)("cm"^3))) * (1.3 * 10^(-3)"moles H"^(+))/(10^3color(red)(cancel(color(black)("cm"^3)))) = color(darkgreen)(ul(color(black)(4 * 10^(-5)"moles H"^(+))))#