Question #34319
1 Answer
Explanation:
As you know, the only criterion that determines the spontaneity of a reaction is the Gibbs free energy change,
color(blue)(bar(ul(|color(black)(DeltaG = DeltaH - T * DeltaS)color(white)(a/a)|)))
Here
Now, in order for a reaction to be spontaneous at a given temperature, it must have
DeltaG < 0
This, of course, implies that a non-spontaneous reaction will have
DeltaG > 0
A positive Gibbs free energy change corresponds to
DeltaH - T * DeltaS > 0
This means that at low temperatures, you have
DeltaH > T * DeltaS
Now, this can be true for
This means that you need
DeltaH - T * DeltaS < 0
or
DeltaH < T * DeltaS
As you can see, this cannot be true if
overbrace(DeltaH)^(color(blue)("negative")) > overbrace(T * DeltaS)^(color(blue)("even more negative")) -> non-spontaneous reaction
However, if
overbrace(DeltaH)^(color(darkgreen)("positive")) < overbrace(T * DeltaS)^(color(darkgreen)("even more positive")) -> spontaneous reaction
Remember,
In general terms, you can have four possible scenarios when dealing with the Gibbs free energy change
DeltaH<0 ,DeltaS>0 -> spontaneous at any temperatureDeltaH>0 ,DeltaS<0 -> non-spontaneous regardless of temperatureDeltaH>0 ,DeltaS>0 -> spontaneous at a certain temperature rangeDeltaH<0 ,DeltaS<0 -> spontaneous at a certain temperature range
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As you can see, reactions that have
In this particular case, the reaction is endothermic, since
A classic example would be the melting of ice, for which
DeltaH > 0 -> you need to add heat to melt iceDeltaS > 0 -> the entropy of the system is increasing because you're going from solid to liquid
However, the melting of ice is only spontaneous when