What is the graphic for f(x,y)=x y^(x/y)=C_0f(x,y)=xyxy=C0 ?

1 Answer
Nov 4, 2016

See below.

Explanation:

Making x = lambda yx=λy and substituting in

f(x,y)=x y^(x/y)=c_0f(x,y)=xyxy=c0 we have

f(lambda y,y)=lambda y y^lambda=lambda y^(lambda+1)=c_0f(λy,y)=λyyλ=λyλ+1=c0

so

y(lambda)=(c_0/lambda)^(1/(lambda+1))y(λ)=(c0λ)1λ+1 and also

x(lambda)=lambda (c_0/lambda)^(1/(lambda+1))x(λ)=λ(c0λ)1λ+1 so we can generate x,yx,y pairs obeying the condition.

f(x,y)=x y^(x/y)=c_0f(x,y)=xyxy=c0

Attached a plot of

x(lambda),y(lambda)x(λ),y(λ) for lambda in [0.1,3]λ[0.1,3]

enter image source here