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Question #197e4

1 Answer

Nov 4, 2016

Calculate the concentration of $H^{+}$ $H^+$ and then take the negative base-10 logarithm to get the pH.

Explanation:

The balanced reaction is
$C H_{3} C O O H (a q) \leftrightarrow H^{+} (a q) + C H_{3} C O O^{-} (a q)$ $CH_3COOH(aq) harr H^+(aq) + CH_3COO^(-)(aq)$

If 5% of the acid ionizes, then the concentration of $H^{+}$ $H^+$ is
$[H^{+}] = 2.0 M \times 0.05 = 0.1 M$ $[H^+]=2.0M times 0.05 = 0.1M$

The ph is then

pH = $- log [H^{+}] = - log (0.1) = 1.0$ $-log[H^+] = -log(0.1) = 1.0$

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