Question #197e4

1 Answer
Nov 4, 2016

Calculate the concentration of H^+H+ and then take the negative base-10 logarithm to get the pH.

Explanation:

The balanced reaction is
CH_3COOH(aq) harr H^+(aq) + CH_3COO^(-)(aq)CH3COOH(aq)H+(aq)+CH3COO(aq)

If 5% of the acid ionizes, then the concentration of H^+H+ is
[H^+]=2.0M times 0.05 = 0.1M[H+]=2.0M×0.05=0.1M

The ph is then

pH = -log[H^+] = -log(0.1) = 1.0log[H+]=log(0.1)=1.0