How do we represent the reduction of $MnO_2$ by chloride anion to give $Mn^(2+)$ and chlorine gas?

Question

2018 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-30T16:15:39

This is a redox reaction: manganese is reduced......

$MnO_2 +4H^+ + 2e^(-) rarr Mn^(2+) + 2H_2O$ $(i)$

...........and chloride ion is oxidized.

$Cl^(-) rarr 1/2Cl_2(g) + e^-$ $(ii)$

$(i) + (ii)xx2:$ (we wish to remove electrons from the final redox equation.

$MnO_2 +4H^+ + 2Cl^(-) rarr Mn^(2+) + Cl_2(g) + 2H_2O$

How do we represent the reduction of MnO_2MnO_2 by chloride anion to give Mn^(2+)Mn^(2+) and chlorine gas?