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Question #189b5

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Feb 22, 2017

Let downward initial velocity of the pebble be #u#

So utilising #h=uxxt+1/2xxgxxt^2# we get

#91.2=uxx4+1/2xx9.8xx4^2#

#=>4u=91.2-8xx9.8#

#=>u=91.2/4-8xx9.8/4#

#=>u=22.8-19.6=3.2"m/s"#

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