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Question #be35b

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Oct 16, 2016

$\sqrt{9} \sqrt{9} \sqrt{9} = 27$ $sqrt(9)sqrt(9)sqrt(9)=27$

Explanation:

Assuming the question is intended as $\sqrt{9} \sqrt{9} \sqrt{9}$ $sqrt(9)sqrt(9)sqrt(9)$ , then we have

$\sqrt{9} \sqrt{9} \sqrt{9} = \sqrt{3^{2}} \sqrt{3^{2}} \sqrt{3^{2}}$ $sqrt(9)sqrt(9)sqrt(9) = sqrt(3^2)sqrt(3^2)sqrt(3^2)$

$= 3 \cdot 3 \cdot 3$ $=3*3*3$

$= 27$ $=27$

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