Question #a18d2

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Answer 1 · 2016-10-13T15:54:05

$"speed : "19.30 " "m/s$

$"displacement : "59" "meters$

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$"the slope of graph is equal to acceleration"$

$tan alpha=3.00=(v_f-4.30)/5$

$3*5=v_f-4.30$

$15=v_f-4.30$

$v_f=15+4.30$

$v_f=19.30" "m/s$

$"area under graph is equal to displacement "$

$delta x=(4.30+19.30)/2*5$

$Delta x=(23.60)/2*5$

$Delta x=59" "meters$

enter image source here

$"or..."$

$v_f=v_i+a*t$

$v_f:"final speed"$

$a:"acceleration"$

$t:"time elapsed"$

$v_f=4.30+3*5$

$v_f=4.30+15$

$v_f=19.30" "m/s$

$Delta x=v_i*t+1/2*a*t^2$

$Delta x=4.30*5+1/2*3*5^2$

$Delta x=21.5+37.5$

$Delta x=59" "meters$