Question #69245

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Doc048
Jul 7, 2017

#LiCl(l) => Li(s) + 1/2Cl_2(g)#

Explanation:

Reduction: #Li^+(l) + e^(-) => Li(s)#

Oxidation: #Cl^(-)(l) => 1/2Cl_2(g) + e^(-)#

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