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What mole is occupied by #1*mol# of gas under standard conditions?

1 Answer

Dec 27, 2016

#V=22.4*dm^3#

Explanation:

#V=(nRT)/P#

#V=(1*cancel(mol)xx0.0821*L*cancel(atm)*cancel(K^-1)*cancel(mol^-1)xx273*cancelK)/(1*cancel(atm))#

#=22.4*L# or #22.4*dm^3#

Note that #1*dm^3=(1xx10^-1*m)^3=1xx10^-3m^3=1*L#, i.e. #1*L=1*dm^3=10^-3m^3#.

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