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Question #969c8

1 Answer

Feb 10, 2017

See below.

Explanation:

e)
#(x^2-16)/(x^2+4)=(x^2+4-20)/(x^2+4)=1-20/(x^2+4)#

#lim_(x->oo)(x^2-16)/(x^2+4)=1-lim_(x->oo)20/(x^2+4)=1#

f)
#lim_(x->0)x^3/(2x+1)=(lim_(x->0)x^3)(lim_(x->0)1/(2x+1))=0 cdot 1=0#

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