Question #969c8 Calculus Limits Introduction to Limits 1 Answer Cesareo R. Feb 10, 2017 See below. Explanation: e) (x^2-16)/(x^2+4)=(x^2+4-20)/(x^2+4)=1-20/(x^2+4) lim_(x->oo)(x^2-16)/(x^2+4)=1-lim_(x->oo)20/(x^2+4)=1 f) lim_(x->0)x^3/(2x+1)=(lim_(x->0)x^3)(lim_(x->0)1/(2x+1))=0 cdot 1=0 Answer link Related questions How doI find limits in calculus? How do limits work in calculus? What exactly is a limit in calculus? What is the purpose of a limit in calculus? What is rational function and how do you find domain, vertical and horizontal asymptotes. Also... lim x-->-1- f(x) = ? How do you use the Squeeze Theorem to show that limsinx/x as x approaches infinity? How do you use the Squeeze Theorem to show that sqrt (x) * e^(sin(pi/x))=0 as x approaches zero? How do you use the Squeeze Theorem to find lim xcos(1/x) as x approaches zero? How do you use the Squeeze Theorem to find lim x^2 (Sin 1/x)^2 as x approaches zero? See all questions in Introduction to Limits Impact of this question 1967 views around the world You can reuse this answer Creative Commons License