Question #3320d

1 Answer
P dilip_k
Oct 11, 2016

120g S_8

Explanation:

The equation of the given reaction is

8SO_2+16H_2S->3S_8+16H_2O

Considering the atomic masses of

S->32" g/mol"

O->16" g/mol"

H->1" g/mol"

We calculate the molar masses of

SO_2->32+2*16=64" g/mol"

H_2S->2*1+32=34" g/mol"

S_8->8*32=256" g/mol"

From the equation of the reaction we get the ratio of no. of moles of

n_(SO_2):n_(H_2S):n_(S_8)=8:16:3

So the ratio of their masses

=m_(SO_2):m_(H_2S):m_(S_8)

=(8xx64):(16xx34):(3xx256)

=16:17:24=80:85:120

The mass of each reactant is 85g .

The ratio of masses as shown above reveals that 85g of H_2S is exhausted when 80g of SO_2 reacts with it and as a result maximum 120g S_8 is produced.

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