Question #98a41

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Answer 1 · 2016-10-07T01:09:56

Let

#u-> "Initial velocity of the ball"=2.2" m/s"#

#v-> "Final velocity of the ball"=0" m/s"#

#s-> "Length of ascent along the slope"=3.2m#

#t-> "Time of ascent along the slope"#

Since the motion occurs with constant retardation,we can write

#1/2(u+v)xxt=s#

#=>1/2(2.2+0)xxt=3.2#

#=>t=3.2/1.1~~2.9s#