Question #d640c

1 Answer
Eddie
Oct 5, 2016

C

Explanation:

Young's Modulus: \lambda stackrel \text{def} = {text{stress}}/{text{strain}} = sigma/epsilon

epsilon = (Delta L)/(L), quad sigma = (F)/(A)

A circular cross-section, but there are 2 of them so A = (pi D^2)/2

implies lambda = ((F)/(A))/((Delta L)/(L)) = (F L)/(A Delta L )

= (2 F L)/(( pi D^2) Delta L )

= (2 (80g) (10))/(( pi 0.005^2)(0.001) ) implies C!!

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