Question #fca8b

1 Answer
P dilip_k
Jan 22, 2017

The displacement (x) of the particle with time (t) along x-axis is given here by the following relation

x=2-5t+6t^2

Differntiating the relation w.r to we get the velocity of the particle at tth instant. So

v(t)=(dx)/(dt)=0-5+12t

Hence initially when t=0 we have velocity
v(0)=-5+12xx0=-5unit

Related questions
See all questions in Displacement and Velocity
Impact of this question
1210 views around the world
You can reuse this answer
Creative Commons License