Question #a7489

1 Answer
P dilip_k
Oct 3, 2016

Percentage Composition of constituent elements in a compound

C->74.0%

H->7.4%

N->8.6%

O->10.0%

Considering their atomic masses as

C->12" g/mol"

H->1" g/mol"

N->14" g/mol"

O->16" g/mol"

Now dividing each percentage composition by the respective atomic mass and then taking the ratio we get the ratio of number of atoms of constituent elements in the compound as

C:H:N:O=74/12:7.4/1:8.6/14:10/16

=6.16:7.4:0.614:0.625

=6.16/0.614:7.4/0.614:0.614/0.614:0.625/0.614

=10:12:1:1

Hence the empirical formula is

C_10H_12NO

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