Question #a7489

1 Answer
P dilip_k
Oct 3, 2016

Percentage Composition of constituent elements in a compound

#C->74.0%#

#H->7.4%#

#N->8.6%#

#O->10.0%#

Considering their atomic masses as

#C->12" g/mol"#

#H->1" g/mol"#

#N->14" g/mol"#

#O->16" g/mol"#

Now dividing each percentage composition by the respective atomic mass and then taking the ratio we get the ratio of number of atoms of constituent elements in the compound as

#C:H:N:O=74/12:7.4/1:8.6/14:10/16#

#=6.16:7.4:0.614:0.625#

#=6.16/0.614:7.4/0.614:0.614/0.614:0.625/0.614#

#=10:12:1:1#

Hence the empirical formula is

#C_10H_12NO#

Related questions
See all questions in Empirical and Molecular Formulas
Impact of this question
2401 views around the world
You can reuse this answer
Creative Commons License