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Question #2c645

1 Answer

Jan 3, 2017

#n=637#

Explanation:

We know that #5^5=3125 > 2557# so the number of trailing zeroes is given by

#n=sum_(k=1)^4 floor(2557/5^k) = 511+102+20+4=637#

which is the number of #5# factors appearing in #2557# Those #5# multiplied by the #2# factors are responsible by the trailing zeroes.

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