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10.00 ml of 0.1089 M oxalic acid neutralises 18.65 ml of sodium hydroxide solution. What is the concentration of the sodium hydroxide ?

1 Answer

Sep 26, 2016

#sf([NaOH]=0.1168color(white)(x)"mol/l")#

Explanation:

#sf(H_2C_2O_(4(aq))+2NaOH_((aq))rarrNa_2C_2O_(4(aq))+2H_2O_((l)))#

#sf(n_(H_2C_2O_4)=cxxv=0.1089xx10.00/1000=0.001089)#

#:.##sf(n_(NaOH)=0.001089xx2=0.002178)#

#sf(c=n/v)#

#:.##sf([NaOH]-=(0.002178)/(0.01865)=0.1168color(white)(x)"mol/l")#

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