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Answer 1 · 2016-09-29T08:47:24

We know molar mass of Hydrogen is $=2g/"mol"$

The amount of hydrogen given is $=4.47xx10^-4g= (4.47xx10^-4g)/(2g/"mol")$
$=2.235xx10^-4mol$

The equation of the reaction

$N_2 + 3H_2 -> 2NH_3$

As per this equation

3 moles $H_2$ produces 2 moles $NH_3$

So
$2.235xx10^-4mol$ H_2 will

produce $2/3xx2.235xx10^-4mol NH_3$

$=2/3xx2.235xx10^-4xx6.023xx10 ^23 " molecules "NH_3$

$~~8.97xx10^23 " molecules " NH_3$