Question #d4b06

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Answer 1 · 2016-09-22T18:22:23

#" Reqd. Lim.="pi.#

Let #pi/x=theta", so that, as "xrarroo, thetararr0.#

Also, #x=pi/theta#

We know that, #lim_(yrarr0)siny/y=1.#

Now, reqd. Lim.#=lim_(thetararr0) pi/theta*sintheta#

#=pi{lim_(thetararr0)sintheta/theta}#

#=pi.#

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