Question #1f4d1
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Explanation:
You can solve this problem by looking at the solubility graph for potassium nitrate,
For starters, the temperature is given to you in Kelvin, so convert it to degrees Celsius
#t[""^@"C"] = "313 K" - "273.15 K" ~~ 40^@"C"#
Now, according to the solubility graph, potassium nitrate has a solubility of about
In other words, an aqueous solution of potassium nitrate will contain a maximum of
You can now use this solubility to figure out how many grams of potassium nitrate can be dissolved in
#50 color(red)(cancel(color(black)("g H"_2"O"))) * "67 g KNO"_3/(100color(red)(cancel(color(black)("g H"_2"O")))) = "34 g KNO"_3#
I'll leave the answer rounded to two sig figs.